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49 minutes ago, The_Teddy_Bear_Muffin said:

You do a thing, then once you've done that thing you do another thing.

Stop

 

 

Can you take a more clear image?


Retard

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Posted  Edited by Ghost_Assassin

Find the area of the circle using the equation A = pi*r^2.

 

A = area

pi = 3.14...

r = radius

 

diameter  =  12

radius = 6

 

One of the angles is 30 degrees of the triangle. Total is 180 degrees inside a triangle.

 

You are given 30 degrees for one of the triangles. You can find the area of the section of the triangle. The one with the central line separating the two areas.

You can then find the section separated from the triangle. Triangle could be isosceles shape so the other angle could be 30 degrees.

 

Add the area of the triangle and area of the sector of the circle together. 

 

https://mathbitsnotebook.com/Geometry/Circles/CRAreaSegmentsSectors.html

 

Edited by Ghost_Assassin

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1 hour ago, Ghost_Assassin said:

Find the area of the circle using the equation A = pi*r^2.

 

A = area

pi = 3.14...

r = radius

 

diameter  =  12

radius = 6

 

One of the angles is 30 degrees of the triangle. Total is 180 degrees inside a triangle.

 

You are given 30 degrees for one of the triangles. You can find the area of the section of the triangle. The one with the central line separating the two areas.

You can then find the section separated from the triangle. Triangle could be isosceles shape so the other angle could be 30 degrees.

 

Add the area of the triangle and area of the sector of the circle together. 

 

https://mathbitsnotebook.com/Geometry/Circles/CRAreaSegmentsSectors.html

 

I figured it out. Thanks 

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Posted  Edited by Joshy

I'm surprised nobody said polar coordinates?  Triangles frighten me.  I'm glad the question was answered :^_^:

Edited by Joshy

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Guest

i remember doing this in calc 3 and then differential equations happened and now i don't remember anything at all.

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