affect 17 / 2,215 Report Post Posted May 24, 2017 Find te area of the shaded region. How do you do it when it's an inscribed angle instead of central? Share this post Link to post Share on other sites More sharing options...
NewNebula12 79 / 4,755 Report Post Posted May 24, 2017 You do a thing, then once you've done that thing you do another thing. Hello from all the animals~ Share this post Link to post Share on other sites More sharing options...
Severely_Artistic 742 / 9,471 Report Post Posted May 24, 2017 49 minutes ago, The_Teddy_Bear_Muffin said: You do a thing, then once you've done that thing you do another thing. Stop Can you take a more clear image? Retard TTT Admin Breach Admin Ragdoll Combat Manager Share this post Link to post Share on other sites More sharing options...
Ghost_Assassin 75 / 3,536 Report Post Posted May 24, 2017 Edited May 24, 2017 by Ghost_Assassin Find the area of the circle using the equation A = pi*r^2. A = area pi = 3.14... r = radius diameter = 12 radius = 6 One of the angles is 30 degrees of the triangle. Total is 180 degrees inside a triangle. You are given 30 degrees for one of the triangles. You can find the area of the section of the triangle. The one with the central line separating the two areas. You can then find the section separated from the triangle. Triangle could be isosceles shape so the other angle could be 30 degrees. Add the area of the triangle and area of the sector of the circle together. https://mathbitsnotebook.com/Geometry/Circles/CRAreaSegmentsSectors.html Edited May 24, 2017 by Ghost_Assassin Share this post Link to post Share on other sites More sharing options...
affect 17 / 2,215 Report Post Posted May 24, 2017 1 hour ago, Ghost_Assassin said: Find the area of the circle using the equation A = pi*r^2. A = area pi = 3.14... r = radius diameter = 12 radius = 6 One of the angles is 30 degrees of the triangle. Total is 180 degrees inside a triangle. You are given 30 degrees for one of the triangles. You can find the area of the section of the triangle. The one with the central line separating the two areas. You can then find the section separated from the triangle. Triangle could be isosceles shape so the other angle could be 30 degrees. Add the area of the triangle and area of the sector of the circle together. https://mathbitsnotebook.com/Geometry/Circles/CRAreaSegmentsSectors.html I figured it out. Thanks Share this post Link to post Share on other sites More sharing options...
Joshy 4,382 / 45,351 Report Post Posted May 25, 2017 Edited May 25, 2017 by Joshy I'm surprised nobody said polar coordinates? Triangles frighten me. I'm glad the question was answered Edited May 25, 2017 by Joshy Share this post Link to post Share on other sites More sharing options...
affect 17 / 2,215 Report Post Posted May 25, 2017 8 minutes ago, Joshy said: I'm surprised nobody said polar coordinates? Triangles frighten me. I'm glad the question was answered Hahaha Share this post Link to post Share on other sites More sharing options...
Guest Report Post Posted May 31, 2017 i remember doing this in calc 3 and then differential equations happened and now i don't remember anything at all. Share this post Link to post Share on other sites More sharing options...